## Discussion Forum

### ZIML Monthly Contest June-2022 Div M Question 10

ZIML Monthly Contest June-2022 Div M Question 10

There are nine letters, "ENDOFYEAR", but there are two letters "E". Will the correct answer be:
5!*2= 240, instead of just 5! = 120?

Thanks.

Re: ZIML Monthly Contest June-2022 Div M Question 10

The two "E"s make things a little tricky here. Note that in a rearrangement the "E"s are identical, as swapping them doesn't change anything.

Let's look at a smaller example, were we can list everything. How many different rearrangements of "ROAR" are there that contain "OAR" in the sequence.

Here there's only $2! = 2$ (not $2!\cdot 2 = 4$) different rearrangements that contain "OAR":

1. ROAR
2. OARR

I think it also helps to list out ALL the different rearrangements of "ROAR" in total (note there are not $4! = 24$ rearrangements, there are $4!\div 2 = 12$ of them:

1. AORR
2. AROR
3. ARRO
4. OARR
5. ORAR
6. ORRA
7. RAOR
8. RARO
9. ROAR
10. RORA
11. RRAO
12. RROA

Hope this helps!

Re: ZIML Monthly Contest June-2022 Div M Question 10

No, since there are two E’s you divide by 2!. This is because you can switch the E’s and it will still be the same case.